Question

the polynomial kx^3+3x^2-8 and 3x^3-5x+8 are divisible by x+2. If the remainder is same in each case, find the value of k​

Answer 1

Answer:

Given polynomials are p(x)=kx

3

+3x

2

−3 and Q(x)=2x

3

−5x+k.

It is also given that these two polynomials leave the same remainder when divided by (x−4), therefore, we equate the polynomials and substitute x=4 as shown below:

k(4)

3

+3(4)

2

−3=2(4)

3

−5(4)+k

⇒64k+48−3=128−20+k

⇒64k+45=k+108

⇒64k−k=108−45

⇒63k=63

⇒k=1

Hence, k=1.

Step-by-step explanation:

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