the polynomial kx³+3x³-3and 2x³-5x+k leave the same remainder when divided by(x-4) find k.
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☆ Solution ==》
Answer:-
k= -3
k= 192
Given=》
▪︎ kx³+3x³-3
▪︎ 2x³-5x+k
☆ x-4
To find =》
value of k
Explanation =》
▪︎ x-4=0
x=4
putting x= 4 p(x)
▪︎ kx³+3x³-3=0
k × (4)³ +3 × ( 4)³-3=0
k×64+3×64-3=0
64k+192=0
64k= -192
k= -192/64
k = -3
putting x=4 in p(x)
▪︎ 2x³-5x+k
2× (4)³-5 ×(4)³+k=0
2×64-5×64+k=0
128-320+k=0
-192+k=0
k=192
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