Question

The polynomial ky3
+ 3y2
– 3 and 2y3

– 5y + k when divided by y – 4 leave the same remainder in each

case. Find the value of k.

Answer 1

Answer:

k =20

Step-by-step explanation:

y-4=0

y = 4

p(y)= -5y + k=0

p(4) = -5×4 +k=0

= -20+ k=0

k=20

Answer 2

Answer:

ky³-3ý²-3 and 2y³-5y+k

divide by x-4

let x-4=0

x=4

now put the valuse of both equations

k.64-48-3

64k-45

in 2nd

2.64-5×4+k

128-20+k

108+k

now equate the equation bcz remider are same

64k-45=108+k

63k=108+45

63k=153

k=153/63