Question

the polynomial p(t)=4t^2-st^2+7 and q(t)=t^2+st+8 leave the same remainder when divided by (t-1) find the value of s​

Answer 1

Step-by-step explanation:

given :

• the polynomial p(t)=4t^2-st^2+7 and q(t)=t^2+st+8

• leave the same remainder when divided by (t-1)

to find :

• find the value of s = ?

• find the value of s = ?

solution :

polynomial is

substitute them :

• polynomial = 4t^2-st^2+7

• quardtic = t^2+st+8

• polynomial = 4(1)³ — s(1)² +7⇒4-s+ 7 = 11 - s

• quardtic = (1)² + s(1) + 8 = 1+ s + 8 = 9+ s

substitute the number :

• 11 - s = 9+ s

then we will add it :

• 11=9+ s + s

• 11 = 9+2s

then we will subtract 11 -9 we will get 2

.then we will divide it with 2 :

• the answer we will get = 1

• so the answer is = 1

Answer 2

Answer:

Hope it's helpful to you.