Question

The polynomial p(x)= ax^3+9x^2 +4x-8 when divided by (x+1), the remainder is -20. Find the value of a.

Answer 1

Answer:

Given p(x) = kx^3 + 9x^2 - 4x - 10.

Given g(x) = x - 3.  

By the remainder theorem, we get  

= > x - 3 = 0  

= > x = 3.  

plug x = 3 in p(x), we get

= > k(3)^3 + 9(3)^2 - 4(3) - 10 = -22  

= > 27k + 81 - 12 - 10 = -22  

= > 27k + 59 = -22  

= > 27k = -81

= > k = -3.  

Therefore the value of k = -3.

Step-by-step explanation:

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Answer 2

Answer:

10

x+1=0

x=-1

3a(-1)+9(-1)×2+4(-1)-8

= -3a+(-9)×