Question

The polynomial p(x)=Kx^3+9x^2+4x-8 when divided by (x+3)leaves a remainder 10(1-k).Find the value of K

Answer 1

$x + 3 = 0 \\ x = - 3 \\ p(x) = k {x}^{3} + 9 {x}^{2} + 4x - 8 \\ p( - 3) = k( { - 3)}^{3} + 9( { - 3)}^{2} + 4( - 3) - 8 = 0 \\ - 27k + 81 - 12 - 8 = 0 \\ - 27k + 61 = 0 \\ - 27k = - 61 \\ k = 2.2$
This is ur answer

Answer 2

Answer:

above ans is right.......