Question

the polynomial p(x) =kxcube+9xsqure+4x-8 when divided by (x+3) leaves a remainder 10(1-k) find the value of k​

Answer 1

Step-by-step explanation:

kx^3+9x^2 +4x-8

x+3=0

x=-3

put value of x

k(-3)^3+9(-3)^2+4(-3)-8=10(1-k)

-27k+81-12-8= 10(1-k)

-27k+61= 10-10k

51= 17k

k= 3

Answer 2

Answer:

p(x)=kx³+9x²+4x-8. g(x)=(x+3)

Step-by-step explanation:

x³

by remainder Thoream g(x)=(x+3)

0=x+3

p(x)=kx³+9x²+4x_3

k×(_3)³+9×(_3)²+4×(_3)_3

_27+81_12_3

_42+81

39

remainder=10(1_k)

0=1_k

_1=k. answer