Math, asked by nafeezsultana4993, 1 year ago

The polynomial p(x) =x^4-2x^3+3x^2-ax+3a-7 is divided by (x-1) leaves the remainder 19. Find the value of a​

Answers

Answered by krishgupta02
5

Answer:a=12

Step-by-step explanation:p(x) =x^4-2x^3+3x^2-ax+3a-7

g(x) =x-1=0

x=1

p(1) =19

p(1) = (1) ^4-2(1)^3+3(1)^2-a(1) +3a-7=19

=1-2+3-a+3a-7=19

=-5+2a=19

=2a=19+5

=2a=24

a=24/2

a=12

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