The polynomial px ² +qx+rx ⁴ +5 is of type
1 point
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Answered by
2
Answer:
biquadratic polynomial
Step-by-step explanation:
hope this will help you
Answered by
0
Answer:
p2+q2=1+9=10
Step-by-step explanation:
The divisor is x4−1=(x−1)(x+1)(x2+1)
By factor theorem, f(1)=f(−1)=0
Thus, 1+p+q−1−1−3=0 and 1+q−1−3=p−1
i.e., p+q=4 and p−q=−2
Adding the two, 2p=2 i.e. p=1 and ∴ q=3.
∴ p2+q2=1+9=10
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