The polynomial which when divided by –x² + x – 1 gives a quotient x – 2 and remainder 3, is
A. x³ – 3x² + 3x – 5
B. –x³ – 3x² – 3x – 5
C. –x³ + 3x² – 3x + 5
D. x³ – 3x² – 3x + 5
Answers
Answered by
22
Answer:
a=bq+r
a= (–x² + x – 1) × (x–2)+3
a=–x³ + x² – x + 2x²– 2x + 2 + 3
[ a=–x³ + 3x² – 3x + 5 ]
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Answered by
9
Given : polynomial which when divided by –x² + x – 1 gives a quotient x – 2 and remainder 3.
Concept :
DIVISION ALGORITHM for polynomials :
f(x) = g(x) × q(x) + r(x)
Dividend = Divisor × Quotient + Remainder
Solution :
We have, g(x) = -x² + x -1 , q(x) = x - 2 and r(x) = 3
f(x) = g(x) × q(x) + r(x)
= (-x² + x -1) (x - 2) + 3
= -x³ + x² - x +2x² -2x + 2 + 3
= -x³ + x² + 2x² - x -2x +2+3
= -x³ + 3x² - 3x +5
Hence, the polynomial f(x) is -x³ +3x² - 3x +5 .
The correct option is (c) : -x³ +3x² - 3x +5 .
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