Math, asked by Akshatvaya5902, 11 months ago

The polynomial which when divided by –x² + x – 1 gives a quotient x – 2 and remainder 3, is
A. x³ – 3x² + 3x – 5
B. –x³ – 3x² – 3x – 5
C. –x³ + 3x² – 3x + 5
D. x³ – 3x² – 3x + 5

Answers

Answered by shubham2931
22

Answer:

a=bq+r

a= (–x² + x – 1) × (x–2)+3

a=–x³ + x² – x + 2x²– 2x + 2 + 3

[ a=–x³ + 3x² – 3x + 5 ]

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Answered by nikitasingh79
9

Given :  polynomial which when divided by –x² + x – 1 gives a quotient x – 2 and remainder 3.

 

Concept :

DIVISION ALGORITHM for polynomials :  

f(x) = g(x)  × q(x) + r(x)

Dividend =  Divisor ×  Quotient + Remainder

 

Solution :  

We have,  g(x) = -x² + x -1 , q(x) = x - 2 and r(x) = 3

 f(x) = g(x)  × q(x) + r(x)

= (-x² + x -1) (x - 2) + 3  

= -x³ + x² - x +2x² -2x + 2 + 3  

= -x³ + x² + 2x² - x -2x +2+3

= -x³ + 3x² - 3x +5

Hence, the polynomial f(x) is -x³ +3x² - 3x +5 .

The correct option is (c) : -x³ +3x² - 3x +5 .

HOPE THIS ANSWER WILL HELP YOU……

 

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If the polynomial  f(x)=ax^{3}+bx-c is divisible by the polynomial  g(x)=x^{2}+bx+c , then ab=

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(d)  -\frac{1}{c}

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