Question

The polynomial whose zeroes are \bold{2+\sqrt{3}} and \bold{2-\sqrt{3}} is \bold{x^{2}-4 x+1}

Answer 1

Answer:

?????????

what type of question is this

Answer 2

Answer:

Polynomial whose roots are a and b is given by

$(x - a)(x - b) = 0$

So required polynomial is

$(x - ( 2 + \sqrt{3}) )(x - (2 - \sqrt{3} )) = 0 \\ (x - 2 - \sqrt{3} )(x - 2 + \sqrt{3} ) = 0 \\ (x - 2) {}^{2} - \sqrt{3} {}^{2} = 0 \\ {x}^{2} - 4x + 4 - 3 = 0 \\ {x}^{2} - 4x + 1 = 0$