the polynomial x^3-mx+4x+6 when divided by x+2 leaves reminder 14 find the value of m
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Answered by
50
HOLA!!!
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HERE YOUR ANSWER IS
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Let p (x) = x^3 -mx +4x+6
x+2= 0
x = -2
p (x) = x^3 - mx +4x+6
p (-2) = (-2)^3 -m (-2)+ 4 (-2) +6
14 = (-8) +2m -8 +6
14 = 2m -16+6
14 = 2m - 10
14 +10 = 2m
24 = 2m
2m = 24
m = 24/2
m = 12
The value of m =12
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In 3rd step you could see that I used 14 instead p (-2)
REMEMBER
we got the remainder 14 when we substitute x= -2 . So we can use it to simplify further.
___________
HOPE IT HELPS YOU :D
_________
HERE YOUR ANSWER IS
____________
Let p (x) = x^3 -mx +4x+6
x+2= 0
x = -2
p (x) = x^3 - mx +4x+6
p (-2) = (-2)^3 -m (-2)+ 4 (-2) +6
14 = (-8) +2m -8 +6
14 = 2m -16+6
14 = 2m - 10
14 +10 = 2m
24 = 2m
2m = 24
m = 24/2
m = 12
The value of m =12
______________
In 3rd step you could see that I used 14 instead p (-2)
REMEMBER
we got the remainder 14 when we substitute x= -2 . So we can use it to simplify further.
___________
HOPE IT HELPS YOU :D
Answered by
4
Answer:
Step-by-step explanation:
answer is x=-2
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