Question

the polynomial x cube minus 3 x square - 3 and 2 x cube minus 5 x + a leave the same remainder in each case when divided by x minus 4 find the value of "a"​

Answer 1

Answer:

a= -95

Step-by-step explanation:

x^3-3x^2-3=f(x)

x-4=0

x=4

4^3-3(4)^2-3

64-48-3

=13(=1)

2x^3-5x+a=f(x)

x=4

2(4)^3-5(4)+a

128-20+a

108+a(=2)

since both the equations have the same remainder

therefore, equation(1)=equation(2)

13=108+a

a=13-108

therefore, a=-95

Hope it helps you