the polynomial x3 +2x2-5ax-8 and x3+ax2-12x-6 when divided by (x-2) (x-3) leaves remainder p and q respectively if q-p=10 find value of a
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x=2
2*3+2*2-5a*2-8
6+4-5a-6
10-5a-6=0
-5a-6=-10
-a-6=-10-5
-a-6=-15
-a=-15+6
-a=-9
2*3+2*2-5a*2-8
6+4-5a-6
10-5a-6=0
-5a-6=-10
-a-6=-10-5
-a-6=-15
-a=-15+6
-a=-9
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