Question

The polynomial x³_mx²+4x+6 when divided by (x+2) leaves remainder 14 find of m​

Answer 1

Answer:

ovsjsbjsjabjsbsjbsbsjusj

Answer 2

Value of m=6

Step-by-step explanation:

Given:-

The polynomial x³_mx²+4x+6 when divided by (x+2) leaves remainder 14

To find:-

Find the valu of m

Solution:-

Given polynomial is p(x)=x³_mx²+4x+6

Given divisor=(x+2)

Given remainder=14

We know that

If p(x) is divided by x-a then the remainder is p(a)- Remainder theorem

Now given p(x) is divided by (x+2) then the remainder is 14

=>p(-2)=14

=>(-2)³-m(-2)²+4(-2)+6=14

=>-8+4m-8+6=14

=>4m-16+6=14

=>4m-10=14

=>4m=14+10

=>4m=24

=>m=24/4

=>m=6

Answer:-

The value of m=6

Used theorem:-

Remainder theorem:-

Let p(x) be a polynomial of degree greater than or equal to 1 and x-a is another linear polynomial then if p(x) is divided by x-a then the remainder is p(a).