Question

The polynomials (2x³+x²-ax+2) and (2x³-3x²-3x+a) when divided by ( x - 2 ) leave the same remainder . Find the value of a .​

Answer 1

Answer:

Step-by-step explanation:

As the remainder is same in each case substitute x = 2

2x^3 + x^2 -ax +2 = 2x^3 - 3x^2- 3x+a

4-2a+2=-12-6+a

3a=24. a=8