Math, asked by hyinterbuilt6751, 1 year ago

The polynomials (ax^3+3x^2-3) and (2x^3-5x+a) when divided by (x-4) leave the same remainder,Find the value of a.

Answers

Answered by hukam0685
9

a({4})^{3}+3({4})^{2}- 3= 2({4})^{3}   \\ -5(4) + a \\ 64a + 48 - 3 = 128 - 20 + a \\
63a = 108 - 45\\ 63a = 63 \\ a = 1
Answered by SRIKRISHIK
6
g(x)=x-4=0
g(x)=4


let ax³+3x²-3 be f(x)
and 2x³-5x+a be h(x)


f(x)=h(x)
as both have same remainder when decided by g(x)


a(4)³+3(4)²-3=2(4)³-5(4)+a
64a+48-3=128-20+a
64a+45=108+a
64a-a=108-45
63a=63
a=63÷63
=1
Hence the value of a is 1
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