The polynomials ax^3-3x^2+4and 2x^3-5x+a when divided by x-2, leaves the remainder p and q respectively.If p-2q=4,find the value of a
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5
Answer:
24/7
Step-by-step explanation:
Using remainder theorem,
a(2)^3 - 3 (2)^2 +4 = p
2(2)^3 - 5(2) + a = q
p-2q = 7a-20 = 4
a = 24/7
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