Question

The Polynomials ax²+3x²-13 and 2x³-5x+a are divided by x+2.What value of 'a' gives the same remainder in each case?​

Answer 1

Answer:

-5/3

Step-by-step explanation:

x+2=0

x=-2

as the polynomials give same remainder

ax² +3x²-13 =2x³-5x+a

a(-2)²+3(-2)²-13=2(-2)³-5(-2)+a

4a+12-13=-16+10+a

4a-a-1=-6

3a=-6+1

3a=-5

a=-5/3