The polynomials ax3+3x2-3 and 2x3-5x+a when divided by (x-4) leave the remainders R1 and R2 respectively. Find the values of 'a ' in each of the following cases, if
R1=R2
R1+R2=0
2R1-R2=0
Answers
Answered by
10
the answer is when R1=R2 a=-1/3 and R1+R2=0 a= -89/5 and 2R1 - R2=0 a = -46/9 im done
Attachments:
Similar questions