The polynomials ax3-3x2+4 and 2x3-5x+a when divided by (x–2) leave the remainders p and q respectively, if p – 2q = 4 ; find the value of a.
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Answered by
368
Solution:-
given by:-
The polynomials ax^3-3x^2+4 and 2x^3-5x+a when divided by (x–2) leave the remainders p and q respectively.
here , x = 2
》ax^3-3x^2+4
》8a -12+4 = p
》8a-8 =p
2x^3-5x+a
》2×8-10+a = q
》a+6 = q
accourding to question:-
》p – 2q = 4
》8a-8 - 2(a+6) = 4
》8a -8-2a-12 =4
》6a = 4+20
》a = 24/6
》(a = 4) ans
☆i hope its help☆
given by:-
The polynomials ax^3-3x^2+4 and 2x^3-5x+a when divided by (x–2) leave the remainders p and q respectively.
here , x = 2
》ax^3-3x^2+4
》8a -12+4 = p
》8a-8 =p
2x^3-5x+a
》2×8-10+a = q
》a+6 = q
accourding to question:-
》p – 2q = 4
》8a-8 - 2(a+6) = 4
》8a -8-2a-12 =4
》6a = 4+20
》a = 24/6
》(a = 4) ans
☆i hope its help☆
Answered by
102
a=4 here is your answer hope this will help you
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