Question

The polynomials kx^3+3x^2-13 & 2x^3-5x+k are divided by (x+2). If the remainder in each case is same, find ‘k’

Answer 1

Answer:

5/9 is the answer of the question

Step-by-step explaination:

$= > k( - 8) + 12 - 13 = - 16 + 10 + k$

$= > 12 - 13 + 16 - 10 = k + 8k$

$= > 28 - 23 = 9k$

$= > 5 = 9k$

$= > k = \frac{5}{9}$