The polynomials p(x) = 4x
^3
– 2x
^2
+ px+ 5 and g (x) = x
^3
+ 6x
^2
+ p leave the remainders
a
^2
and b respectively, when divided by (x+2). Find the value of p if a + b = 0.
jaladiprathibhasagar:
hi
Answers
Answered by
1
Step-by-step explanation:
Remainder theorem:
When we divide f(x) by (x−c) , the remainder f(c)
When p(x)=4x
3
−2x
2
+px+5 is divided by (x+2), the remainder is
p(−2)=4(−2)
3
−2(−2)
2
+p(−2)+5
=−2p−35
So,
a=−2p−35
When q(x)=x
3
+6x
2
+p is divided by (x+2), the remainder is
q(−2)=(−2)
3
+6(−2)
2
+p
=p+16
So,
b=p+16
Now
a+b=0
−2p−35+p+16=0
−p−19=0
p=−19
pls check, the remainder for p(x)=a^2, not a
Hey unicorn what do you mean yaar
from which country you are
the remainder when u divide p(x) by x+2 is a^2 (a square), u have taken as 'a'
that is why even i had problem finding solution for it
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