The polynomials p (x)= ax^3+3x^2-3 and q (x) = 2x^3 -5x + a when divided by (x-4) leave the remainder r1+ r2=0. Find a
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Given that r₁ and r₂ are the remainder of The polynomials p (x)= ax^3+3x^2-3 and q (x) = 2x^3 -5x + a when divided by (x-4).
So using remainder theorem we know that
when p (x)= ax^3+3x^2-3 divided by x-4, so
r₁ = p(4)
⇒ r₁ = a(4)³+3(4)²-3
⇒ r₁ = 64a+48-3
⇒ r₁ = 64a+45 ...(1)
when q (x) = 2x^3 -5x + a divided by x-4, so
r₂ = q(4)
⇒ r₂ = 2(4)³-5(4)+a
⇒ r₂ = 128-20+a
⇒ r₂ = 108+a ...(2)
Given that r₁+r₂ = 0
64a+45+108+a = 0 [ using (1) and (2) ]
⇒ 65a = -153
⇒ a = -153/65
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