the polynomials p(x)=p(x^2+qx+6)when divided by (x-3)leaves remainder 3
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Hi ,
It is given that ,
p( x ) = x² + qx + 6
If p( x ) is divided by ( x - 3 ) leaves the
remainder 3
p( 3 ) = 3
3² + q × 3 + 6 = 3
9 + 3q + 6 = 3
15 + 3q = 3
3q = 3 - 15
3q = - 12
q = - 12/3
q = - 4
Therefore ,
q = -4
I hope this helps you.
: )
It is given that ,
p( x ) = x² + qx + 6
If p( x ) is divided by ( x - 3 ) leaves the
remainder 3
p( 3 ) = 3
3² + q × 3 + 6 = 3
9 + 3q + 6 = 3
15 + 3q = 3
3q = 3 - 15
3q = - 12
q = - 12/3
q = - 4
Therefore ,
q = -4
I hope this helps you.
: )
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thanks
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