Question

The polynomials p(x) = x3 + 2x2 – 5x - 7 and q(x) = x3 + x2

- 12x + 6, when divided by

(x + 1) and (x - 2) respectively give the remainders R1 and R2.

Find 2R1 + R2 .

A. -8

B. 8

C. -2

D. None of these​

Answer 1

Answer:

Correct option is

A

2

Let p(x)=x

3

+2x

2

−5ax−7

and q(x)=x

3

+ax

2

−12x+6 be the given polynomials,

Now, R

1

= Remainder when p(x) is divided by x+1.

⇒R

1

=p(−1)

⇒R

1

=(−1)

3

+2(−1)

2

−5a(−1)−7[∵p(x)=x

2

+2x

2

−5ax−7]

⇒R

1

=−1+2+5a−7

⇒R

1

=5a−6

And R

2

= Remainder when q(x) is divided by x-2

⇒R

1

=q(2)

⇒R

2

=(2)

3

+a×2

2

−12×2+6[∵q(x)=x

2

+ax

2

−12x−6]

⇒R

2

=8+4a−24+6

⇒R

2

=4a−10

Substituting the values of R

1

and R

2

in 2R

1

+R

2

=6, we get

⇒2(5a−6)+(4a−10)=6

⇒10a−12+4a−10=6

⇒14a−22=6

⇒14a−28=0

⇒a=2

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Answer 2

Step-by-step explanation:

I hope this will help you and answer is none of these