the polynomials
and
when divided by (x-2) leave the same remainder. Find the value of 'a'.
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Let the given polynomial be f(x) & g(x). When f(x) & g(x) are divided by (x-2) they have the same remainder
x - 2 = 0 ; x = 2
So, f(2)= g(2)
2x³ + x²- ax + 2 = 2x³ - 3x² - 3x + a
2(2)³ + (2)² - a(2) + 2 = 2(2)³ - 3(2)² - 3(2) + a
16 + 4 - 2a + 2 = 16 - 12 - 6 + a
22 - 2a = -2 + a
-2a - a = -2 - 22
- 3a = -24
a = 24/3
a = 8
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