Question

The polynomials x + 2x2 + k-1 and 2x + kr +x when divided by (x - 2) leave the same remainder in

each case. Find the value of k.​

Answer 1

Answer:

1

Step-by-step explanation:

Answer

Given polynomials are p(x)=kx

3

+3x

2

−3 and Q(x)=2x

3

−5x+k.

It is also given that these two polynomials leave the same remainder when divided by (x−4), therefore, we equate the polynomials and substitute x=4 as shown below:

k(4)

3

+3(4)

2

−3=2(4)

3

−5(4)+k

⇒64k+48−3=128−20+k

⇒64k+45=k+108

⇒64k−k=108−45

⇒63k=63

⇒k=1

Hence, k=1.