Math, asked by yuvrajdas999, 1 month ago

The polynomials x3 + 2x2-5ax -7 and x3 + ax2 –12x +6 when divided by x + 1 and x – 2 respectively, leave remainders R1 and R2 respectively. Find the value of a in each of the following cases:

i. R1 = R2

ii. R1 + R2 =0

iii. 2R1 + R2= 0​

Answers

Answered by THADIK
0

Step-by-step explanation:

r1=-1

r2=1

2r1+r2 =0hjk office f Vic give log hi

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