The polynomials x3 + 2x2 - 5ax – 8 and x3 + ax2 -12x -6 when divided by
(x - 2) and (x + 1) leave remainders p and q respectively. If q - p = 8, find the
value of a.
Answers
Answered by
12
Answer:
1.If x-2 is g(x), x=2.
p(2)=x³+2x²-5ax-8=p
(2)³+2(2)²-5(2)a-8=p
8+8-10a-8=p
8-10a=p----(1)
2.If x+1 is g(x), x=-1.
p(-1)=x³+ax²-12x-6=q
(-1)³+(-1)²a-12(-1)-6=q
-1+a+12-6=q
a+5=q-----(2)
Now,q-p=8
so, (2)-(1)=8
a+5-(8-10a)=8
a+5-8+10a=8
11a=8+3=11
a=1.
Hope helps u.
Plz mark as brainliest.
Answered by
2
Answer:
answer attached in photo
Attachments:
Similar questions