Math, asked by johny67791, 7 months ago

The polynomials x3 + ax2 + 4x - 1 and 2x3 - x2 + 7a both leave the same remainder when divided by x-2.
What is the value of a?

Answers

Answered by shristirajpoot789
1

Answer:

x=2

8+4a+8-1=32-4+7a

-13/3=a

Answered by Kartikempire
0

Answer:

a = 1

Step-by-step explanation:

So,

x3 + ax2 + 4x - 1 = 2x3 - x2 + 7a

(2)^3 +a(2)^2 +4(2) -1 = 2(2)^3 -(2)^2 +7a

8 + 4a +8 -1 = 16 -4 +7a

3 = 3a

1 = a

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