The polynomials x3 + ax2 + 4x - 1 and 2x3 - x2 + 7a both leave the same remainder when divided by x-2.
What is the value of a?
Answers
Answered by
1
Answer:
x=2
8+4a+8-1=32-4+7a
-13/3=a
Answered by
0
Answer:
a = 1
Step-by-step explanation:
So,
x3 + ax2 + 4x - 1 = 2x3 - x2 + 7a
(2)^3 +a(2)^2 +4(2) -1 = 2(2)^3 -(2)^2 +7a
8 + 4a +8 -1 = 16 -4 +7a
3 = 3a
1 = a
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