The popoulation of Hyderabad was 6809000 in the year 2011.If it increases at the rate of 4.7% per annum.What will be the population at the end of the year 2015.
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Answered by
6
We need to calculate the population of Hyderabad after 4 years with the given rate of increase given as 4.7%.
We will use the compounding formula:
Z = A (1 + r/100)^t
where Z is the population at the end of the duration
A is the starting population
r is the rate of increase
t is the time period in years
Please note 4.7% = 0.047
Population at the end of the year 2015 = (6809000)()
Solving this we get the population of Hyderabad at the end of year 2015 as 8182199
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harsha0101:
how you got answer
Increase rate = 4.7 % per annum
Time difference = 4 years
Population increase in 1 year =
4.7 /100 × 6809000
= 320023.
Therefore population increase in 4 years =
320023 × 4 = 1280092.
Therefore the population at the end of 2015
= 6809000 + 1280092
= 8089092 .
Hope this helps you. ...
Read more on Brainly.in - https://brainly.in/question/5604868#readmore
Answered by
7
Population of Hyderabad in 2011 = 6809000
Increase rate = 4.7 % per annum
Time difference = 4 years
Population increase in 1 year =
4.7 /100 × 6809000
= 320023.
Therefore population increase in 4 years =
320023 × 4 = 1280092.
Therefore the population at the end of 2015
= 6809000 + 1280092
= 8089092 .
Hope this helps you. ...
Increase rate = 4.7 % per annum
Time difference = 4 years
Population increase in 1 year =
4.7 /100 × 6809000
= 320023.
Therefore population increase in 4 years =
320023 × 4 = 1280092.
Therefore the population at the end of 2015
= 6809000 + 1280092
= 8089092 .
Hope this helps you. ...
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