Math, asked by abhiram3682, 1 year ago

The Population In A Village Was 10000 One Year Ago The Population At Present Is 9780.Find The Decreasing Rate.

Answers

Answered by Agastya0606
2

Answer:

2.2%

Step-by-step explanation:

Population of the village 1 year ago was 10,000.

Present population of the village is 9780.

Let the rate of decreasing population be r %.

According to the formula of Compound Interest of uniform decrease,

p(1-r/100)^n , where p= principal

                    r=rate of increase/decrease

                    n= time taken

Now, according to the given problem we have to find the rate at which population has decreased in one year.

So, 9780=10000(1-r/100)^1

   9780/10000= (1-r/100)^1

   0.978= 1-r/100

   -1+0.978= -r/100

    -0.022= -r/100

    0.022*100 = r

    2.2=r

So, the rate at which population has decreased in one year is 2.2%

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