The Population In A Village Was 10000 One Year Ago The Population At Present Is 9780.Find The Decreasing Rate.
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Answer:
2.2%
Step-by-step explanation:
Population of the village 1 year ago was 10,000.
Present population of the village is 9780.
Let the rate of decreasing population be r %.
According to the formula of Compound Interest of uniform decrease,
p(1-r/100)^n , where p= principal
r=rate of increase/decrease
n= time taken
Now, according to the given problem we have to find the rate at which population has decreased in one year.
So, 9780=10000(1-r/100)^1
9780/10000= (1-r/100)^1
0.978= 1-r/100
-1+0.978= -r/100
-0.022= -r/100
0.022*100 = r
2.2=r
So, the rate at which population has decreased in one year is 2.2%
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