The population of a bacteria is dish A is 3.2 x 10^8 and in dish B is 0.7 x 10^7. What is the total polpulation of bacteria in both the dishes?
Answers
Answered by
9
Answer:
mark me as brainlist
Step-by-step explanation:
The population of a bacteria is dish A is 3.2 x 10^8 and in dish B is 0.7 x 10^7. What is the total polpulation of bacteria in both the dishes?
Answered by
7
Answer:
10^7(32.7)
Step-by-step explanation:
3.2×10^8+0.7×10^7=10^7(3.2×10+0.7)
10^7(32+0.7)
10^7(32.7)
Similar questions
English,
3 months ago
Math,
3 months ago
World Languages,
8 months ago
Science,
11 months ago
Political Science,
11 months ago
Physics,
11 months ago