The population of a certain city is 125000. if the amount birth rate is 3.3% and the annuals death rate is 1.3% calculate the population after 3years.
Answers
Answered by
27
Heya ❗
here's your answer ❗
Present population of the city (p) = 125000
Time(n) = 3 years,
Rate of birth (R₁) = 3.3%
Rate of death (R₂) = 1.3
so, the net rate of increase (R₁ - R₂)
= 3.3 - 1.3 = 2%
Population after 3 years = 125000(1 - 2/100)³
= 125000 × (1.02)³
= 125000 × 1.061208
= 132651
glad help you
it help you,
thank you☺
@vaibhavhoax
here's your answer ❗
Present population of the city (p) = 125000
Time(n) = 3 years,
Rate of birth (R₁) = 3.3%
Rate of death (R₂) = 1.3
so, the net rate of increase (R₁ - R₂)
= 3.3 - 1.3 = 2%
Population after 3 years = 125000(1 - 2/100)³
= 125000 × (1.02)³
= 125000 × 1.061208
= 132651
glad help you
it help you,
thank you☺
@vaibhavhoax
Answered by
10
Heya!
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▪Given that ->
==============
=> Present Population ( p ) -> 125000
=> R1 -> 3.3%
=> R2 -> 1.3%
=> Time ( n ) -> 3 years
=> Total Increase in Population = Birth Rate ( R1 ) - Death Rate ( R2 )
=> 3.3 - 1.3 = 2%
Now Using the Formula =>
↪Substituting the Values ->
A = 125000 × ( 1 - 2/100 )³
A = 125000 × ( 1.02)³
A = 125000 × 1.061
A = 132651
♦Hence the population After A Span of 3 Years is 132651 .
=========================================================
--------
=======================================================
▪Given that ->
==============
=> Present Population ( p ) -> 125000
=> R1 -> 3.3%
=> R2 -> 1.3%
=> Time ( n ) -> 3 years
=> Total Increase in Population = Birth Rate ( R1 ) - Death Rate ( R2 )
=> 3.3 - 1.3 = 2%
Now Using the Formula =>
↪Substituting the Values ->
A = 125000 × ( 1 - 2/100 )³
A = 125000 × ( 1.02)³
A = 125000 × 1.061
A = 132651
♦Hence the population After A Span of 3 Years is 132651 .
=========================================================
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