Question

The population of a certain city is 4096000. If
the annual birth rate is 6.7% and the annual
death rate is 0.45%. Calculate the population
after 2 years.
plz answer with explanation ​

Answer 1

population = 4096000

after a year = 409600+274432-18432=4352000

2nd year = 4352000+291584-19584=4624000

Answer 2

Answer:

$population \: of \: city \: = 4096000 \\ birth \: rate \: of \: city = 6.7\% \\ death \: rate \: of \: city = 0.45\% \\ population \: increase \: after \: 2 \: years = 2 \times (6.7\% \: of \: 4096000) \\ 2( \frac{67}{1000} \times 4096000) \\ 2(67 \times 4096) \\ 2 \times 274432 \\ \\ population \: decrease \: in \: 2 \: year = 2(0.45\%of \: 4096000) \\ 2( \frac{45}{10000} \times 4096000) \\ 2(4.5 \times 4096) \\ 2 \times 18432 \\ 36864 \\ \\ total \: population \: after \: 2 \: years \: = 4096000 + (274432 - 36864) \\ 4096000 + 237568 \\ 4333568$

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