Question

The population of a certain town doubles every decade. If the population of the tow in 2016 was 52,000, what was the population of the town in 1986?​

Answer 1

Answer:

8666.6

Step-by-step explanation:

1 decade=10 years

2016-1986=30 years

1 decade=10 years

30 years=30/10=3 decades

doubles=3*2=6

52,000/6=8666.6

the population in 1986  is 8,666

Answer 2

Step-by-step explanation:

The population of the town every decade forms a GP

Let the population of the town in 1986 be a

Common ratio=r=2

Considering the population of the town as the nth term,

n={(2016-1986)/10}+1

=(30/10)+1

=3+1

=4

ar^(n-1)=52,000

=>a×2^(4-1)=52,000

=>a×2^3=52,000

=>a×8=52,000

=>a=52,000÷8

=>a=6,500________(ans)