The population of a certain town was 50,000. In a year , male population was increased by 5% and female population was increased by 3%. Now the population became 52020. Then what was the number of males and females in the previous year? ........
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8
Answer:
No of males=100x=100*260=26,000
No of females=50000-26000=24,000
Step-by-step explanation:
I believe the following is easy ,Still I have attached the filled sheet
Let in the previous year males are 100x and female are 100y
Then 100x+100y=50,000
100(x+y)=50,000
x+y=500
y=500-x.....................(1)
Now increse in males=5% of 100x=100x*5/100=5x
Increase in females= 3% of 100y=100y*3/100=3y
Total population becomes
50000+5x+3y=52020
Putting value of y from(1)
5x+3*(500-x)=52020-50000
5x+1500-3x=2020
2x=2020-1500=520
x=520/2=260
Thus in the previous year
No of males=100x=100*260=26,000
No of females=50000-26000=24,000
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2
Answer:
x = -260
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