the population of a certain town was 50000 in a year male population was increased by 5% and female population was increased by 3% now the population became 52020 then what was the number of male and female in the previous year
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Answered by
128
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Answered by
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Solution :-
Let the female population of the town be x
Then, the male population will be (50000 - x)
Now, according to the question.
⇒ (50000 - x) × 105/100 + x × (103/100) = 52020
⇒ (5250000 - 105x)/100 + 103x/100 = 52020
⇒ 5250000 - 105x + 103x = 52020*100
⇒ - 2x = 5202000 - 5250000
⇒- 2x = - 48000
⇒ 2x = 48000
⇒ x = 48000/2
⇒ x = 24000
So, female population was 24000
Male population was 50000 - 24000
= 26000
Answer.
Let the female population of the town be x
Then, the male population will be (50000 - x)
Now, according to the question.
⇒ (50000 - x) × 105/100 + x × (103/100) = 52020
⇒ (5250000 - 105x)/100 + 103x/100 = 52020
⇒ 5250000 - 105x + 103x = 52020*100
⇒ - 2x = 5202000 - 5250000
⇒- 2x = - 48000
⇒ 2x = 48000
⇒ x = 48000/2
⇒ x = 24000
So, female population was 24000
Male population was 50000 - 24000
= 26000
Answer.
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