the population of a certain town was 50000 in a year male population was increased by 5% and female population was increased by 3% now the population became 52020 then what was the number of male and female in the previous year
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The population of a certain town was 50,000. In year, the male population increased by 5% and the female population increased by 8%. Now the population becomes 53,220. What was the number of male and female in the previous year.
Solution:
Male population =x
Female population=y
x+y=50,000
y=50,000−x
x increased 5%
y increased 8%
(x+x×5%)+(y+y×8%)=53220
x+
100
5x
+y+
100
8y
=53220
100x+5x+100y+8y=5322000
as y=50,000−x
100x+5x+108(50,000−x)=5322000
105x−108x+5400000=5322000
5400000−5322000=3x
78000=3x
x=26000
y=50,000−x=50,000−26000
y=24000
∴ Male population=26000
Female population=24000
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Answer:
male=26000
female=24000
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