Question

the population of a city according to 1971 census
was 84,500 and it increase to 1,11,200 in 1981 find the percentage increase in the proportion​

Answer 1

Answer:

increase in population= 111200-84500= 26700

% of population increases=26700/84500*100= 31.59%

Step-by-step explanation:

population in 1971=84500

population in 1981=111200

increase in population= 111200-84500= 26700

% of population increases=26700/84500*100= 31.59%