Question

The population of a city according to 1971 census was 84500 and it was 1,11,200 in 1981
Find the percentage increase in population​

Answer 1

Answer:

The increase is 26700.

Therefore the increased percentage is 31.5%.

Step-by-step explanation:

Thanks

Answer 2

Given:

The population of a city according to the 1971 census was 84500 and it was 1,11,200 in 1981

To Find:

Find the percentage increase in population​

Solution:

A percentage is a form of ratio which is expressed in terms of the fraction of 100. It is represented by %. They are dimensionless. The percentage can be denoted by the formula as,

$Percentage=\frac{value}{Total} *100$

To get the percentage increase we use the formula as,

$\% increase=\frac{change}{initial} *100$

So according to the question, the population increased from 84500 to 111200 so the change is,

Change=111200-84500

            =26700

Now using the formula the % increase will be,

$\% increase=\frac{26700}{84500} *100\\=31.59\%$

Hence, the percentage increase in population is 31.59%.