Question

the population of a city in2007 was 1800000 and in 2018 2100000 what is the increase in percent of the population of the city​

Answer 1

Step-by-step explanation:

no.of increased people =2100000-1800000=300000

that amount as a percent 300000/1800000 . 100%= 16.6%

Answer 2

Before finding the answer. Let's find out on how we can find our answer.

• First, we must find subtract population in 2007 with 2018.
• Then, we must calculate the percentage by the formula of

$\sf \dfrac{population \: increased}{total \: population} \times 100$

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Given :

Population in 2007 = 1800000

Population in 2018 = 2100000

To find :

Increase Percentage of Population

Solution :

Increased Population = 2100000 - 1800000

= 300000

$\sf \: population = \dfrac{population \: increased}{total \: population} \times 100$

$\sf = \dfrac{300000}{1800000} \times 100$

$\sf = \dfrac{30000000}{1800000}$

$\sf \: = 6\%$

Hence, the Population Increased Percentage is 6%

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