Question

the population of a city increases at the rate of 5% per annum if the population in 2003 is 52920 what was the population in year 2001​

Answer 1

Answer:

HERE IS UR ANSWER.......

Population in 2001 = 54000 / [1 + 5/100]^2 ; as it is 2 years ago

                               => 54000 / 1.1025

                                   = 48,980

Thus, Population in 2001 = 48,980

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Answer 2

Answer:

59535

Step-by-step explanation:

Given:

we use formula of amount of compound interest to find population 

A( 2003)= 54,000,

R =5%, 

n = 2 years

In 2001 Population would be less than 2003 in two years.

A(2003)= P(2001)(1+R/100)^n

54000 = P (2001)(1+5/100)²

54000 = P(2001)(1+1/20)²

54000= P(2001)(21/20)²

54000 = P(2001)((21×21)/(20×20))

P(2001)=( 54000×20×20)/21×21

Population in 2001 = 48979.59= 48980(approx)

(ii) ATQ, population is increasing. Therefore population in 2005,

A(2005)= P(1+R/100)^n

= 54000(1+5/100)²

= 54000(1+1/20)²

= 54000( 21/20)²

= 54000(21/20)× (21/20)

=( 54000× 441)/ 400

=( 540×441)/4

= 238140/4

= 59535

Population in 2005= 59535

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