Question

The population of a city increases by 10% annually. If it is 31200 now, then its

approximate population two years ago was?​

Answer 1

312000 this is answer

Answer 2

Answer:

25785 approx.

Step-by-step explanation:

Let the population before two years ago be x

Given the population increases by 10%

So increase in population after one year is

100+10×x=0.1x

So population after one year is x+0.1x=1.1x

Increase in population after another one year is

100+10×1.1x=0.11x

So population at present is 1.1x+0.11x=1.21x

But given population at present is 31200

⟹1.21x=31200

⟹ x= 31200÷ 1.21

=25785.124 or 25785

Population of city two years ago is 25785.