Question

the population of a city increases by 10% annually if the present population is 65000 what will be its population after 2 years​


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Answer 1

Answer:

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Answer 2

$\red{\:❥ᴀɴsᴡᴇʀ}$

78650

Step-by-step explanation:

Since, the population is,

$=P(1+r)^tA=P(1+r)$

Where,

P = initial population,

r = rate of increasing per period,

t = number of periods,

Here, P = 65000, r = 10% = 0.1, t = 2,

Hence, the population after 2 years would be,

$</p><p>A=65000(1+0.1)^2A=65000(1+0.1) 2$

$</p><p></p><p>=65000(1.1)^2=65000(1.1) 2$

$</p><p>=65000\times 1.21=65000×1.21$

$= 78650$

I hope it is helpful for you

@ Aman jha.