Question

the population of a city increases by 10% annually if the present population is 65000 what will be its population after 2 years

Answer 1

Here's your answer...
10% of 65000
=10/100×65000
=6500
According to this population increase annually =6500

so, population after two year=6500×2=13000

Hope this helps....

Answer 2

Answers

Present population is=65000

%increase annually=10%

10%of 6500=10/100×65000

=6500

After 2 year= 65000+6500=71500

After2

10/100×71500=7150

71500+7150=78650