The population of a city increases by 5% every year. If the present
population is 540000. Find the population after 2 years.
Answers
Answered by
1
Amount = P(1 + r/100)^n
➡ 540000 (1 + 5/100)^2
➡ 540000 (21/20)^2
➡ 540000 * 441/400
➡ 595350
So the population after 2 years is 595350
➡ 540000 (1 + 5/100)^2
➡ 540000 (21/20)^2
➡ 540000 * 441/400
➡ 595350
So the population after 2 years is 595350
Answered by
1
5%of 540000
=(5/100)×540000
=27000
Population after 2 years,
=2×27000+540000
=54000+540000
=594000
KapilSwami:
wrong answer
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