Question

The population of a city increases each year by 4% of what it had been in the beginning of each year. If the population in 1997 had been 6760000, find the population of the city 1999​

Answer 1

Answer:

Population of the city in 2001 = P \[\left( 1 + \frac{R}{100} \right)^2 \]

\[ = 6760000 \left( 1 + \frac{4}{100} \right)^2 \]

\[ = 6760000 \left( 1 . 04 \right)^2 \]

\[ = 7311616\]

Thus, Population of the city in 2001 is 7311616.

\[(ii)\]

Population of the city in 1997 = P \[\left( 1 + \frac{R}{100} \right)^{- 2} \]

\[ = 6760000 \left( 1 + \frac{4}{100} \right)^{- 2} \]

\[ = 6760000 \left( 1 . 04 \right)^{- 2} \]

\[ = 6250000\]

Thus, Population of the city in 1997 is 6250000.

Step-by-step explanation:

Thus, Population of the city in 2001 is 7311616. Thus, Population of the city in 1997 is 6250000.