Question

The population of a city increases every year at the rate of 10%. If the population now is 1250000 what will be the population after 4 year

Answer 1

Answer:

Population after 4 years = 18,30,125

Step-by-step explanation:

This is a case of compounded growth.

P = initial population = 1250000

R = rate of increase per cent per year = 10

T = time period in years = 4

A = final population at the end of 4 years = ?

Now,

A = P(1 + R/100)^T

A = 1250000*(1 + 10/100)^4

A = 1250000*(1.1)^4

   = 1250000*(1.4641)

   = 1830125

Population at the end of 4 years = 1830125

Answer 2

Answer:

Anser is 1830125

Step-by-step explanation:

1

The population of a town increases every year by 10%. If the present population is 180,000, what will be the population of the town after 2 years?

Let the population of the town after 2 years be x

Increase percent of population every year = 10%

Present population = 180000

= 10% of 180000

= 10/100 * 180000 = 10*1800 = 18000

Increase in population after 1 year = 180000+18000 = 198000

Increase in population afer 2 years = 10% of population in 1 year + population of 1 year

= 10% of 198000+198000

= 10/100 * 198000 = 10*1980 = 19800

= 198000+19800 = 217800

Therefore, the population of the town after 2 years is 2,17,800.